(i) `[Fe(CN)_(6)]^(4-)` and `[Fe(H_(2)O)_(6)]^(2+) ` are of differet colours in dilute solution. Why? (ii) A complex is prepared by mixig `CoCl_(3)` and `NH_(3)` in the molar ratio of 1: 2. 0.1 M solution of this complex was foind to be freeze at `-0.372^(@) C`. What is the formula of the complex ? `K_(f)= 1.86^(@)C/M`
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(i) In both the cases Fe is in +2 state, it has 4 unpaired electrons but `CN^(-)` and `H_(2)O` has different crystal field splitting energy. (ii) `DeltaT_(f)=i.K_(f)m` i= 2 means complex dissociate into two ions. Hence the formula is `[Co(NH_(3))_4(Cl_2)]Cl`
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[Fe(CN)_(6)]^(4-) and [Fe(H_(2)O)_(6)]^(2+) are of different colours in dilute solutions why?
A complex is prepared by mixing CoCl_(3) & NH_(3) 0.1 M solution of the complex was found to freeze at -0.372^(º)C . Total geometrical isomers of complex and x. (Molar depression constant of water = 1.86^(º)C//m ) Report your answer by multiplying x with 6.
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