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How would you prepare : (i) C(6)H(5)NH...

How would you prepare :
(i) `C_(6)H_(5)NH_(2) from C_(6)H_(5)NO_(2)`
(ii) `CH_(3)NH_(2) from C_(2)H_(5)NH_(2)`
(iii)` C_(2)H_(5)NH_(2) from CH_(3)NH_(2)`

Text Solution

AI Generated Solution

To prepare the compounds as specified in the question, we can follow these steps: ### (i) Preparation of C₆H₅NH₂ (Aniline) from C₆H₅NO₂ (Nitrobenzene) 1. **Reduction of Nitrobenzene**: - Start with nitrobenzene (C₆H₅NO₂). - Reduce nitrobenzene using a reducing agent such as iron (Fe) in the presence of hydrochloric acid (HCl) or catalytic hydrogenation (H₂/Pd). - This reaction will convert the nitro group (-NO₂) into an amino group (-NH₂), yielding aniline (C₆H₅NH₂). ...
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Arrange the following in increasing order of their basic strength: (i) C_(2)H_(5)NH_(2),C_(6)H_(5)NH_(2),NH_(3),C_(6)H_(5)CH_(2)NH_(2)and(C_(2)H_(5))_(2)NH (ii) C_(2)H_(5)NH_(2),(C_(2)H_(5))_2NH,(C_(2)H_(5))_(3)N,C_(6)H_(5)NH_(2) (iii) CH_(3)NH_(2),(CH_(3))_(2)NH,(CH_(3))_(3)N,C_(6)H_(5)CH_(2)NH_(2^.)

The number of amines having pK_(b) less than C_(6)H_(5)NH_(2) among the following is P-CH_(3) C_(6)H_(5)NH_(2), o-CH_(3)C_(6)H_(4)NH_(2), m-CH_(3)C_(6)H_(4)NH_(2), C_(6)H_(5)N (CH_(3)) _(2), C_(6)H_(5)NHCH_(3), p-NO_(2)C_(6)H_(4)NH_(2), p-CIC_(6)H_(4)NH_(2), C_(6)H_(5)CH_(2)NH_(2)

Complete the following reaction equations : (i) C_(6)H_(5)N_(2)Cl+CH_(3)COCl to (ii) C_(2)H_(5)NH_(2)+C_(6)SO_(2)Cl to (iii) C_(2)H_(5)NH_(2)+HNO_(2)to