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A hemispherical body of radius R is plac...

A hemispherical body of radius R is placed in a uniform electric field E. If the field E is parallel to the base of the hemisphere the flux linked with it is

A

`2piRE`

B

`2piR^(2)E`

C

`piR^(2)E`

D

zero

Text Solution

AI Generated Solution

The correct Answer is:
To find the electric flux linked with a hemispherical body of radius \( R \) placed in a uniform electric field \( E \) that is parallel to the base of the hemisphere, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Configuration**: - We have a hemisphere with its flat base facing downwards and the curved surface facing upwards. The electric field \( E \) is directed parallel to the flat base of the hemisphere. 2. **Electric Flux Definition**: - Electric flux \( \Phi \) through a surface is defined as: \[ \Phi = \int \vec{E} \cdot d\vec{A} \] - For a uniform electric field, this simplifies to: \[ \Phi = E \cdot A \cdot \cos \theta \] - Where \( A \) is the area of the surface and \( \theta \) is the angle between the electric field and the normal to the surface. 3. **Analyzing the Flat Base**: - For the flat base of the hemisphere, the area vector \( d\vec{A} \) is directed perpendicular to the base (upwards), while the electric field \( \vec{E} \) is parallel to the base (horizontally). - Therefore, the angle \( \theta \) between \( \vec{E} \) and \( d\vec{A} \) is \( 90^\circ \). 4. **Calculating Flux through the Base**: - Since \( \cos 90^\circ = 0 \), the flux through the flat base is: \[ \Phi_{\text{base}} = E \cdot A \cdot \cos 90^\circ = 0 \] 5. **Analyzing the Curved Surface**: - For the curved surface of the hemisphere, the electric field lines enter and exit the surface. - The flux entering the curved surface is equal to the flux exiting the surface. Thus, the net flux through the curved surface is also zero. 6. **Total Electric Flux**: - Since both the flat base and the curved surface contribute zero flux, the total electric flux linked with the hemisphere is: \[ \Phi_{\text{total}} = \Phi_{\text{base}} + \Phi_{\text{curved}} = 0 + 0 = 0 \] ### Conclusion: The electric flux linked with the hemispherical body in the given uniform electric field is: \[ \Phi = 0 \]
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