A deuteron and an `alpha`-particle are placed in an electric field.The forces acting on them are `F_(1)` and `F_(2)` and their accelerations are `a_(1)` and `a_(2)` respectively.
(i) `F_(1) = F_(2)`
(ii) `F_(1) != F_(2)`
(iii) `a_(1) = a_(2)`
(iv) `a_(1) != a_(2)`

Options

A. `barF_(1)=barF_(2)`
B. `barF_(1)+barF_(2)=0`
C. `|bara_(1)|=|bara_(2)|`
D. `|bara_(1)|ge|bara_(2)|`

Answer

B