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In the above question, if the sheets wer...

In the above question, if the sheets were thick and conducting , value of E in the space between the two sheets would be

A

`2sigma //in_(0)`

B

`sigma //in_(0)`

C

zero

D

`4sigma //in_(0)`

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The correct Answer is:
To determine the electric field \( E \) in the space between two thick conducting sheets, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Setup**: - We have two thick conducting sheets placed parallel to each other. Let's denote the charge density on the positive sheet as \( +\sigma \) and on the negative sheet as \( -\sigma \). 2. **Electric Field Due to a Single Sheet**: - The electric field \( E \) due to an infinite sheet of charge with surface charge density \( \sigma \) is given by the formula: \[ E = \frac{\sigma}{2\epsilon_0} \] - This electric field points away from the sheet if the charge is positive and towards the sheet if the charge is negative. 3. **Calculating the Electric Field Between the Sheets**: - For the positive sheet with charge density \( +\sigma \): - The electric field in the region between the sheets (towards the negative sheet) is: \[ E_1 = \frac{\sigma}{2\epsilon_0} \] - For the negative sheet with charge density \( -\sigma \): - The electric field in the same region (towards the negative sheet) is: \[ E_2 = \frac{\sigma}{2\epsilon_0} \] - Since both electric fields are in the same direction (towards the negative sheet), we can add them together. 4. **Net Electric Field Calculation**: - The total electric field \( E \) in the space between the two sheets is: \[ E = E_1 + E_2 = \frac{\sigma}{2\epsilon_0} + \frac{\sigma}{2\epsilon_0} = \frac{2\sigma}{2\epsilon_0} = \frac{\sigma}{\epsilon_0} \] 5. **Conclusion**: - Therefore, the value of the electric field \( E \) in the space between the two thick conducting sheets is: \[ E = \frac{\sigma}{\epsilon_0} \]
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