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The total electric flux through a cube w...

The total electric flux through a cube when a charge 8q is placed at one corner of the cube is

A

`q/(8 epsilon_(0))`

B

`q/(epsilon_(0))`

C

`Q/(2epsilon_(0))6 a^(2)`

D

`(2q)/(epsilon_(0))`

Text Solution

Verified by Experts

The correct Answer is:
A
Since if charge q is placed at the corner of a cube then charge enclosed `=q//8`
Therefore `phi_("cube")=(q_("enclosed"))/(epsilon_(0))=q/(8epsilon_(0))`
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Knowledge Check

  • The total electric flux through a cube when a charge 8q is placed at one comer of the cube is

    A
    `epsilon_0q`
    B
    `epsilon_0/q`
    C
    `4piepsilon_0q`
    D
    `q/epsilon_0`

  • Electric flux through a cube with charge q inside is

    A
    `(q)/(epsi_(0))`
    B
    `(q)/(6epsi_(0))`
    C
    `(q)/(3 epsi_(0))`
    D
    0

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    A
    Electric flux linked with individual faces of the cube may be zero
    B
    Electric flux linked with individual faces of the cube may be non-zero
    C
    Electric flux linked with a certain face of the cube may be `q//8epsilon_0`
    D
    Electric flux linked with a certain face of the cube may be `q//24epsilon_0`

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