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The total electric flux through a cube w...

The total electric flux through a cube when a charge 8q is placed at one corner of the cube is

A

`q/(8 epsilon_(0))`

B

`q/(epsilon_(0))`

C

`Q/(2epsilon_(0))6 a^(2)`

D

`(2q)/(epsilon_(0))`

Text Solution

Verified by Experts

The correct Answer is:
A
Since if charge q is placed at the corner of a cube then charge enclosed `=q//8`
Therefore `phi_("cube")=(q_("enclosed"))/(epsilon_(0))=q/(8epsilon_(0))`
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