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The ionisation potential of mercury is 1...

The ionisation potential of mercury is 10.39 V. How far an electron must travel in an electric field of `1.5 xx 10^(6) V//m` to gain sufficient energy to ionise mercury ?

A

`10.39/(1.6xx10^(-19))m`

B

`10.39/(2xx1.6xx10^(-19))m`

C

`10.39xx1.6xx10^(-19)m`

D

`10.39/(1.5xx10^(6))m`

Text Solution

Verified by Experts

The correct Answer is:
D
`p=sqrt(3)ql`
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