A thin conducting ring of radius `R` is given a charge `+Q`, Fig. The electric field at the center `O` of the ring due to the charge on the part `AKB` of the ring is `E`. The electric field at the center due to the charge on part `ACDB` of the ring is

Options

A. 3E along KO
B. E along OK
C. E along KO
D. 3E along OK

Answer

B

Explanation

As the ring is conducting, so electric field at its centre is zero.
i.e. ,`E_("total")=0 `or `E_(AKB)+E_(ACDB)=0`
or `E_(ACDB)=-E_(AKB)`
or `E_(ACDB)=-E` (along KO)
Therefore the electric field at the centre due to the charge on the part ACDB of thering is E along OK.