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Two identical charged spheres suspended from a common point by two mass-less strings of length `l` are initially at a distance d ( `d ltlt l`) apart because of their mutual repulsion . The charge begins to leak from both the spheres at a constant rate. As a result the charge approach each other with a velocity `v`. Then as a function of distance `x` between them .

A

`v oo x^(-1//2)`

B

`voox^(1//2)`

C

`voox`

D

`voox^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A

`F=(Kq^(2))/(x^(2))=mg tan theta, (dF)/(dq)=0`
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