Find the magnetic induction due to a straight condutor of length `16cm` carrying current of `5A` at a distance of `6cm` from the midpoint of conductor.

Explanation

`B = (mu_0)/(4 pi) I/r (sin theta + sin theta) " but " sin theta = 8/10 = 4/5`

`B = 10^(-7) xx (5)/(6 xx 10^(-2) ) x 2 xx 4/5 = 40/3 mu T`