If a straight conductor of length `40cm` bent in the form of a square and the current `2A` is allowed to pass through square, then find the magnetic induction at the centre of the square loop.

Explanation

`B_("net") = 4 xx (mu_0)/(4pi) xx (I)/(L//2) (sin 45^@ + sin 45^@)`
` = 4 xx (mu_0)/(4pi) xx (I)/(L//2) (sqrt2) = (mu_0)/(4pi) (8sqrt2 I)/(L)`
` = 10^(-7) xx 8 2 sqrt2 xx 2 xx 10 = 16 sqrt2 mu T`