Figure shows a square current carrying loop `ABCD` of side `2m` and current` i=(1)/(2)A`. The magnetic moment `vec(M)` of the loop is

Explanation

`DA = 2 cos 30^@ hati -2 sin 30^@ hatk = (-sqrt3 hati - hatk)`
`vec(AB) = 2hatj therefore vecM = i(vec(DA) xx vec(AB) )`
` = 1/2 [ (-sqrt3 hati - hatk) xx (2hatj) ]`
`=-sqrt3k +hati = (i-sqrt3 hatk)A - m^2`