If two charged particles each of charge `q` mass `m ` are connected to the ends of a rigid massless rod and is rotated about an axid passing through the centre and `_|_` to length. Then find the ratio of magnetic moment to angular momentum.

Explanation

`M = "niA" = 2xx q/t pi (l/2)^2 = 2 xx (qomega)/(2pi) (pil^2)/(4) = (q omegal^2)/(4)`
` L = 2 (mr^2 omega) = 2 (m (l^2)/(4) omega) = (ml^2 omega)/(2) , M/L = (q)/(2m)` .