A solenoid of length `8 cm` has 100 turns in it. If radius of coil is `3 cm` and if it is carrying a current of `2A`, find the magnetic induction at a point `4 cm` from the end on the axis of the solenoid.

Explanation

`B = (mu_0 "ni" )/(2) (sin alpha + sin beta) `
` = (4pi xx 10^(-7) xx 100 xx 2 )/(2) xx 2 xx 4/5 = 64 pi mu T`