A long straight conductor carrying a current of `2A` is in parallel to another conductor of length `5 cm`. And carrying a current `3A`. They are separated by a distance of `10 cm`. Calculate `(a)B` due to first conductor at second conductor `(b)` the force on the short conductor.

Explanation

Given `i_1 = 2Al i_2 = 3A`
` r = 10 cm = 10 xx 10^(-2) m, l_2 = 5cm`
`a) B = (mu_0i_1)/(2pi r) = 2 xx 10^(-7) xx (2)/(10 xx 10^2) = 4 xx 10^(-6) ` Tesla
b) ` F = (mu_0i_1 i_2)/(2pi r) xx l_2`
` = 2 xx 10^(-7) xx (2 xx 3)/(10 xx 10^(-2) ) xx 10^(-2) = 6 xx 10^(-7) N`