A galvanometer of resistance `95 Omega`, shunted resistance of `5 Omega`, gives a deflection of `50` divisions when joined in series with a resistance of `20 k Omega` and a `2 V` accumulator. What is the current sensitivity of the galvanomter (in div`//mu A`)?

Explanation

In accordance with given problem, the situation is depicted by the circuit diagram in fig. As here `20 k Omega` is much greater than the resistance of shunted galvanometer (`lt5 Omega` ), the current in the circuit will be ` l = (2)/(20 xx 10^3) = 10^(-4) A = 100 mu A ` and as this current produces deflection of 50 divisions in the galvanometer
`CS = theta/I = (50div)/(100muA) = (1div)/(2muA)`