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A galvanometer of resistance 20Omega is ...

A galvanometer of resistance `20Omega` is shunted by a `2 Omega` resistor. What part of the main current flows through the galvanometer ?

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`(i_g)/(i) = (G)/(G+S) ` . Given `G = 20 Omega , S = 2 Omega`
` therefore (i_g)/(i) = 2/22 =1/11 , 1/11 th` part of current is passing through galvanometer .
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