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A galvanometer has a resistance of 98Ome...

A galvanometer has a resistance of `98Omega`. If `2%` of the main current is to be passed through the meter, what should be the value of the shunt ?

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`G = 98 Omega , (i_g)/(i) xx 100 = 2%`
` s = (G)/( (i)/(i_g) - 1) , therefore (i)/(i_g) = 100/2 = 50 therefore S = (98)/(50 - 1) = 2 Omega `
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