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An electron of charge e moves in a circu...

An electron of charge `e` moves in a circular orbit of radius `r` round a nucleus the magnetic field due to orbit motion off the electron at the site of the nucleus is `B`. The angular velocity `omega` of the electron is

A

`omega = (mu_0 eB)/(4pi r) `

B

`omega = (mu_0 eB)/(pi r)`

C

`omega = (4pi rB)/(mu_0 e)`

D

`omega = (2pi r B)/(mu_0 e)`

Text Solution

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The correct Answer is:
C
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