If an electron is revolving in a circula...

If an electron is revolving in a circular orbit of radius `0.5A^(@)` with a velocity of `2.2xx10^(6)m//s`. The magnetic dipole moment of the revolving electron is

`8.8 xx 10^(-24) Am`

`8.8 xx 10^(-23) Am`

`8.8 xx 10^(-22) Am`

`8.8 xx 10^(-21) Am`

Verified by Experts

The correct Answer is:

`M = "inA and " I = q/ T`

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If an electron is revolving in a circularr orbit of radius 0.5 A. with a velocity of 2.2 xx 10^(6) m/s. The magnetic dipole moment of the revolving electron is

`8.8 xx 10^(-24)` Am

`8.8 xx 10^(-23)` Am

`8.8 xx 10^(-22)` Am

`8.8 xx 10^(-21)` Am

`(evr)/(2)`

`efpir^(2)`

both 'a' and 'b'

neither 'a' not 'b'

`(eL)/(2m)`

`(e)/(2m)`

`(e)/(2ML)`

`(e)/(mL)`