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A proton enters a magnetic field with a ...

A proton enters a magnetic field with a velocity of `2.5 xx10^(7)ms^(-1)` making an angle `30^(@)` with the magnetic field. The force on the proton is `(B=25T)`

A

`1.25 xx 10^(-11) N`

B

`25 xx 10^(-11) N`

C

`5.0 xx 10^(-11) N`

D

`7.5 xx 10^(-11) N`

Text Solution

Verified by Experts

The correct Answer is:
C
`F = BqV sin theta `
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