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Three long straight conductors are kept ...

Three long straight conductors are kept perpendicular to the plane of paper. Currents `2A,3A` are passing through the two conductors into the plane of paper in first two conductors and `5A` current passes through thirst conductor, directed out of the paper. A closed loop encloses the conductors, then the value of `oint bar(B). bar(dl)` over the closed loop is `(` assume current into the paper as negative and out of the paper as positive `)`

A

`2 mu_0`

B

`0`

C

`-mu_0`

D

`+mu_0`

Text Solution

Verified by Experts

The correct Answer is:
B

`oint B.dl = mu_0i`
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