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A particle of charge 16xx10^(-18) coulom...

A particle of charge `16xx10^(-18)` coulomb moving with velocity `10m//s` along the `x-` axis enters a region where a magnetic field of induction B is along the `y-` axis, and an electric field of magnitude `10//m^(-1)` is along the negative `Z-` axis. If the charged particle continues moving along the `X-` axis, the magnitude to B is

A

`1Wb//m^2`

B

`10^5 Wb//m^2`

C

`10^6 Wb//m^2`

D

`10^(-3) Wb//m^2`

Text Solution

Verified by Experts

The correct Answer is:
A
`V = E/B`
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