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A galvanometer has a resistance 50 Omega...

A galvanometer has a resistance `50 Omega` and it shunted by a `0.5Omega` resistor. The fraction of the main current that flows throught the galvanometer is

A

1/100

B

1/101

C

`1//10`

D

`1//11`

Text Solution

Verified by Experts

The correct Answer is:
B
`i_g = (iS)/(G + S)`
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