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A galvanometer has a resistance of 49Ome...

A galvanometer has a resistance of `49Omega`.If `2%` of the main current is to be passed through the meter, The value of the shunt will be

A

`2Omega `

B

`1Omega`

C

`1//2 Omega `

D

`1//4 Omega `

Text Solution

Verified by Experts

The correct Answer is:
B
`i_g = (iS)/(G + S)`
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