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A galvanometer of internal resistance 10...

A galvanometer of internal resistance `100 Omega` has a full scale deflection current of `1mA`. To convert it into a voltmeter of range `0-10V`, the resistance to be connected is

A

9000 `Omega` in Series

B

10,000 `Omega` in Series

C

9,900 `Omega ` in Series

D

9,800 `Omega ` in Series

Text Solution

Verified by Experts

The correct Answer is:
C
`R = (V)/(i_g) - G`
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