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A particle of mass 1xx10^(26)kg and char...

A particle of mass `1xx10^(26)kg` and charge `1.6xx10^(-19)C` travelling with a velocity `1.28xx10^(6)cm^(-1)` along the positive `X-` axis enters a region in which a uniform electric field `vec(E)=-102.4xx10^(3)k NC^(-1)` and magnetic field `B=8xx10^(-2)jWbm^(-2)`, the direction of motion of the particle is `:`

A

x-axis

B

y-axis

C

z-axis

D

`- x - ` axis

Text Solution

Verified by Experts

The correct Answer is:
A
`V = E/B`
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Knowledge Check

  • An electron has mass 9xx10^(-31)kg and change 1.6xx10^(-19)C is moving with a velocity of 10^(6)m//s , enters a region where magnetic field exists. If it describes a circle of radius 0.10m , the intensity of magnetic field must be

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  • A particle of mass 6.4xx10^(-27) kg and charge 3.2xx10^(-19)C is situated in a uniform electric field of 1.6xx10^5 Vm^(-1) . The velocity of the particle at the end of 2xx10^(-2) m path when it starts from rest is :

    A
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  • An electron (=9xx10^(-31)kg,e=1.6xx10^(-19)) is moving in a circular in a magnetic field of 1.0xx10^(-7)Wb//m^(2) . Its period of revolution is

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    B
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    D
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