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A proton of energy 8 eV is moving in a c...

A proton of energy `8 eV` is moving in a circular path in a uniform magnetic field. The energy of an alpha particle moving in the same magnetic field and along the same path will be

A

4eV

B

2eV

C

8eV

D

6eV

Text Solution

Verified by Experts

The correct Answer is:
C
`Bqv = (mv^2)/(r ) `
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