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A moving coil galvanometer A has 200 tur...

A moving coil galvanometer `A` has 200 turns and resistance `100 Omega`. Another meter `B` has 100 turns and resistance `40 Omega`. All the other quantities are same in both the cases. The current sensitivity of

A

B is double as that of A

B

A is 2 times of B

C

A is 5 times of B

D

B is 5 times of A.

Text Solution

Verified by Experts

The correct Answer is:
B

`theta/I = (NAB)/(C )`
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Knowledge Check

  • A moving coil galvanometer A has 100 turns and resistance 10Omega . Another goal galvanometer B has 50 turns and 5 Omega . The other quantities are same in both the cases. Then the voltange sensitivity of

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