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Due to a straight vertical current carry...

Due to a straight vertical current carrying conductor, a null point occurred at P on east of the conductor. The net magnetic induction at a point `'Q'` which is at same distance on north of the conductor is

A

0

B

`sqrt3 B_H`

C

`B_H`

D

`sqrt2 B_H`

Text Solution

Verified by Experts

The correct Answer is:
D
`R = sqrt(B^2 + B_H^2) = sqrt(B_H^2 + H_H^2) = sqrt2B_H`
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