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Electrons accelerated by a potential dif...

Electrons accelerated by a potential differnece V enter a uniform magnetic field of flux density B at right angles to the field. They describe a circular path of radius `'r'`. If now `'V'` is doubled and B is also doubled, the radius of the new circular path is

A

`4r`

B

`2r`

C

`2 sqrt2r`

D

`r//sqrt2`

Text Solution

Verified by Experts

The correct Answer is:
D
`r_1/r_2 = sqrt(V_1/V_2 xx (B_2^2)/(B_1^2) )`
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