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A beam of protons enters a uniform magne...

A beam of protons enters a uniform magnetic field of 0.3T with velocity of `4xx10^5m//s` in a direction making an angle of `60^(@)` with the direction of magnetic field. The path of motion of the particle will be

A

4.7m

B

0.47m

C

0.047m

D

0.0047 m

Text Solution

Verified by Experts

The correct Answer is:
C
`P = v cos theta xx T , T = (2pi r)/(v sin theta)`
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