Home
Class 12
PHYSICS
An electron travelloing with a velocity ...

An electron travelloing with a velocity `bar(V)=10^(7) hat(i)m//s` enter a magnetic field of induction `bar(B)=bar(2j)`. The force on electron is

A

`1.6 xx 10^(-12) vecj N`

B

`3.2 xx 10^(-12) vecK N`

C

`6.4 xx 10^(-12) vecK N`

D

`-3.2 xx 10^(-12) vecK N`

Text Solution

Verified by Experts

The correct Answer is:
D

`F = q(vecV xx vecB)`
Promotional Banner

Topper's Solved these Questions

  • MOVING CHARGES AND MAGNETISM

    NARAYNA|Exercise EXERCISE - 3|29 Videos
  • MOVING CHARGES AND MAGNETISM

    NARAYNA|Exercise EXERCISE - 4|20 Videos
  • MOVING CHARGES AND MAGNETISM

    NARAYNA|Exercise EXERCISE - 2(H.W) (SOLENOID AND TOROID)|2 Videos
  • MAGNETISM AND MATTER

    NARAYNA|Exercise EXERCISE - 4 (SINGLE ANSWER TYPE QUESTION)|17 Videos
  • NUCLEAR PHYSICS

    NARAYNA|Exercise LEVEL-II-(H.W)|9 Videos

Similar Questions

Explore conceptually related problems

A bar magnet of moment bar(M) is in a magnetic field of induction bar(B) . Then the couple is

An electron moves with velocity vec(v) = ak In a magnetic field of intensity vec(B) = b hat(i) + c hat(j) . Find the magnetic force on the electron.

An electron moving with a velocity V_(1)=hat im/s at a point in a magnetic field experiences a force bar(F)= (-ehat j) Newton where 'e' is the charge of the electron.If the electron moves with a velocity bar(V)_(2)=2 hat k m/s at the same point the force experienced by it is

An electron moving with a velocity V_(1)=hat im/s at a point in a magnetic field experiences a force bar(F)=(-ehat j) Newton where 'e' is the charge of the electron.If the electron moves with a velocity bar(V)_(2)=2hat km/s at the same point the force experienced by it is

An alpha particle is moving with a velocity of (7 xx 10^(5) hat i m//s) in a magnetic field of (5 hat i + 9 hat j ) . T . Find the magnetic force acting on the particle.

An alpha particle is moving with a velocity of (7 xx 10^(5) hat I m//s) in a magnetic field of (5 hat I + 9 hat j) T. Find the magnetic force acting on the particle.

A "bar" magnet of moment bar(M)=hat(i)+hat(j) is placed in a magnetic field induction vec(B)=3hat(i)+4hat(j)+4hat(k) . The torque acting on the magnet is

A particle is moving with velocity bar(v)=hat(i)+3hatj and it produces an electrostatic field at a point given by bar(E)=2hat(k) . It will produce magnetic field at that point equal to (all quantities are in S.I. units and speed of light is c )

An electron enters an electric field having intensity vec(E )= (3 hat(i) + 6hat(j) +2 hat(k)) Vm^(-1) and magnetic field having induction vec(B)= (2 hat(i) + 3hat(j)) T with a velocity vec(V)= (2 hat(i) + 3hat(j)) ms^(-1) . The magnitude of the force acting on the electron is (Given e= -1.6 xx 10^(-19)C )