A current carrying closed loop in the from of a right angle isoseles triangle `ABC` is placed in a unifrom magnetic fild acting along `AB`. If the magnetic force on the arm `BC` is `F`, the force on the arm `AC` is

Options

A. `vecF`
B. `sqrt2 F`
C. `-sqrt2 vecF`
D. `-vecF`

Answer

D

Explanation

For an current carrying loop in magnetic field = 0
` vecF_("net") = 0`
` because vecF_("net") = vecF_(AB) + vecF_(BC) + vecF_(AC)`
`because F_(AB) = 0 `(angle between `vecB " and " vec(dl) = 0)`
So , `vecF_(AC) = - vecF_(BC) = - F`