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A wire carrying current I has the shape...

A wire carrying current `I` has the shape as shown in the adjoining figure. Linear parts of the wire are very long and parallel to X-axis while semicicular portion of radius `R` is lying in `Y-Z` plane. Magnetic field at point `O` is

A

`vecB = - (mu_0)/(4pi ) I/R ( pi hati + 2 hatk )`

B

`vecB = (mu_0I)/(4pi R) (pi hati - 2 hatk)`

C

`vecB = (mu_0 I)/(4pi R) (pi hati + 2 hatk )`

D

`vecB = - (mu_0 I)/(4pi R) (pi hati - 2 hatk)`

Text Solution

Verified by Experts

The correct Answer is:
A

`vecB_1` = magnetic field at O due to current in parallel wires
`vecB_2` = magnetic field due to semi - circular wire
` vecB_1 = vecB_1 + vecB_2`
` = - (mu_0 i)/(2pi R) (hatk) - (mu_0 i)/(4R) (hati)`
` = - (mu_0 i)/(4pi R) (pi hati + 2hatk) `
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