A magnet is suspended at an angle `60^(0)` in an external magnetic field of `5xx10^(-4)T`. What is the work done by the magnetic field in bringing it in its direction? `["The magnetic moment"=20A-m^(2)]`

Explanation

Work done by the magnetic field,
`W=MB(costheta_(1)-costheta_(2))" ""Here " theta_(1)=60^(0)andtheta_(2)=0^(@)`
`thereforeW=20xx5xx10^(-4)[cos60^(@)-cos0^(@)]`
= `10^(-2)[1/2-1]=-5xx10^(-3)J`.