A magnetic field of `1600Am^-1` produces a magnetic flux of `2*4xx10^-5` weber in a bar of iron of cross section `0*2cm^2`. Calculate permeability and susceptibility of the bar.

Explanation

Magnetic induction, `B=phi/A=(2.4xx10^(-5))/(0.2xx10^(-4))=1.2Wb//m^(2)`
i) Permeability, `mu=B/H=1.2/1600=7.5xx10^(-4)TA^(-1)m`
ii) As `mu=mu_(0)(1+chi)` then
Susceptibility, `X=mu/mu_(0)-1=(7.5xx10^(-4))/(4pixx10^(-7))-1=596.1`