A bar magnet of magnetic moment M and mo...

A bar magnet of magnetic moment `M` and moment of inertial `I` is in the direction of magnetic meridian. If the magnet is displaced by a very small angle `(theta)`, the angular acceleration is (Magnetic induction of earth's horizontal field `=B_(H)`)

`(MB_(H)theta)/I`

`(IB_(H)theta)/M`

`(Mtheta)/(IB_(H))`

`(Itheta)/(MB_(H))`

Text Solution

Verified by Experts

The correct Answer is:

`Ialpha=MB_(H)theta`

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NARAYNA-MAGNETISM AND MATTER-EXERCISE - 1 (H.W)

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