A short bar magnet is placed with its south pole facing geographic south and the distance between the null point is found to be `16 cm`. When the magnet is turned pole to pole at the same place then the distance between the null points will be

Options

A. will be same, along the axial line
B. will be same, along the equatorial line
C. will be `16xx2^(1//3)`, on the axial line
D. will be `16xx2^(1//3)`, on the equatorial line

Answer

C

Explanation

`B_(H)=B_(e)=(mu_(0)2M)/(4pid_(1)^(3))" "B_(H)=B_(a)=(mu_(0)M)/(4pid_(2)^(3))`