Home
Class 12
PHYSICS
Total energy of density of electromagnet...

Total energy of density of electromagnetic waves in vacuum is given by the relation

A

`(1)/(2), (E^(2))/(epsilon_(0)) + (B^(2))/(2 mu_(0))`

B

`(1)/(2) epsilon_(0) E^(2) + (1)/(2) mu_(0) B^(2)`

C

`(E^(2) + B^(2))/(c ) `

D

`(1)/(2) epsilon_(0) E^(2) + (B^(2))/(2mu_(0))`

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Topper's Solved these Questions

  • ELECTROMAGNETIC WAVES

    NARAYNA|Exercise C.U.Q|39 Videos
  • ELECTROMAGNETIC WAVES

    NARAYNA|Exercise EXERCISE -1(C.W)|32 Videos
  • ELECTROMAGNETIC WAVES

    NARAYNA|Exercise EVALUATE YOURSELF - 1|5 Videos
  • ELECTROMAGNETIC INDUCTION

    NARAYNA|Exercise ASSERTION & REASON|6 Videos
  • ELECTROSTATIC POTENTIAL AND CAPACITANCE

    NARAYNA|Exercise ADDITIONAL PROBLEMS|14 Videos

Similar Questions

Explore conceptually related problems

The velocity of electromegnetic waves in vacuum is given by :

The speed of electromagnetic wave in vacuum

Light is an electromagnetic wave. Its speed in vacuum is given by the expression

Velocity of electromagnetic waves in vacuum depends upon

Speed of electromagnetic waves is given

Energy of electromagnetic waves is due to their

The electric field part of an electromagnetic wave in vacuum is given by E = 6 cos [1.2 ("rad")/(m) y + 3.6 xx 10^(8) ("red")/(s) t ] hat(i) (N)/(C ) , then find i) frequency of propagation (f) (ii) Ampitude of magnetic field in electromagnetic wave