An object of length 10 cm is placed at right angles to the principal axis of a mirror of radius of curvature 60 cm such that its image is virtual, erect and has a length 6cm. What kind of mirror is it and also determine the position of the object?

Explanation

To solve the problem, we will follow these steps:

### Step 1: Identify the type of mirror
Given that the image is virtual, erect, and smaller than the object, we can conclude that the mirror is a **convex mirror**. Convex mirrors always produce virtual, erect, and diminished images.

### Step 2: Use the magnification formula
The magnification (m) of a mirror is given by the formula:
\[ m = \frac{h'}{h} = -\frac{v}{u} \]
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