An equilateral glass prism is made of a material of refractive index 1.500. Find its angle of minimum deviation.

Explanation

`A=60^@, mu=1.5,delta_(min)=?`
substuting `mu=(sin((A+delta_(min))/2))/(sin(A/2))`
`1.5=(sin((60^(@)+delta_(min))/2))/(sin(60^@/2))` `1.5sin30^@`
`sin((60^@ + delta_(min))/2)=1.5xx0.5000=0.75`
`implies delta_(min)=37^@10.`