A ray of light undergoes a deviation of `30^@` when incident on an equilateral prism of refractive index `sqrt(2)`.
What is the angle subtended by the ray inside the prism with the base of the prism?

Explanation

Here `delta=30^@` and `A=60^@`. So if the prism had been in minimum deviation.
`mu-(sin[(30^@ + 60^@)//2])/(sin(60^@//2))=(sin45^@)/(sin30^@)=1/sqrt(2)xx2=sqrt(2)`
The prism position is in the minimum diviation position implies that
`r_(1)=r_(2)=r=(A/2)=(60^@/2)=30^@`
Therefore, angle subtended by the ray inside the prism with the surface A b gt (90°-r) = (90°-30°) = 60° and as base also subtends an angle of 60° with the face AB,the ray inside the prism is parallel to the base, ie. the angle subtended by the ray inside the prism with base is zero.