A telescope objective of focal length 1 m forms a real image of the moon 0.92cm in diameter. Calculate the diameter of the moon taking its mean distance from the earth to be `38xx10^(4)`km If the telescope uses an eyepiece of 5cm focal length, what would be the distance between the two lenses for (i) the final image to be formed at infinity (ii) the final image(virtual) at 25 cm form eye.

Explanation

To solve the problem step-by-step, we will break it down into parts:

### Step 1: Calculate the Diameter of the Moon

1. **Given Data**:
- Focal length of the objective lens, \( f_o = 1 \, \text{m} = 100 \, \text{cm} \)
- Diameter of the image formed by the objective lens, \( d = 0.92 \, \text{cm} \)
- Mean distance from Earth to the Moon, \( u_0 = -38 \times 10^4 \, \text{km} = -38 \times 10^9 \, \text{cm} \)
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