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A plot of modulus of image distance vers...

A plot of modulus of image distance versus object distance for a spherical mirror is a:

A

Straight Line

B

Circle

C

Parabola

D

Hyperbola

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The correct Answer is:
To solve the question regarding the plot of the modulus of image distance versus object distance for a spherical mirror, we will follow these steps: ### Step 1: Understand the Mirror Formula The mirror formula relates the object distance (u), image distance (v), and focal length (f) of a spherical mirror: \[ \frac{1}{v} + \frac{1}{u} = \frac{1}{f} \] From this, we can express \( v \) in terms of \( u \): \[ \frac{1}{v} = \frac{1}{f} - \frac{1}{u} \] This can be rearranged to: \[ v = \frac{fu}{u - f} \] ### Step 2: Analyze the Equation The equation \( v = \frac{fu}{u - f} \) indicates that as \( u \) approaches \( f \), \( v \) approaches infinity. This suggests a hyperbolic relationship because the image distance \( v \) will not be defined when \( u = f \). ### Step 3: Consider the Modulus Since the question asks for the modulus of the image distance, we will consider \( |v| \). The relationship remains: \[ |v| = \left| \frac{fu}{u - f} \right| \] This means that the graph will still exhibit hyperbolic characteristics, as the absolute value does not change the nature of the relationship. ### Step 4: Plot the Graph To plot the graph of \( |v| \) versus \( u \): - When \( u = 0 \), \( |v| \) is undefined (as \( v \) approaches infinity). - When \( u = f \), \( |v| \) is also undefined (as \( v \) approaches infinity). - For values of \( u \) less than \( f \), \( |v| \) will be negative, but since we are taking the modulus, it will be positive. - For values of \( u \) greater than \( f \), \( |v| \) will be positive. ### Step 5: Conclusion The plot of \( |v| \) versus \( u \) will resemble a hyperbola, with branches in the first and second quadrants, indicating that as the object distance increases or decreases away from the focal point, the image distance behaves hyperbolically. ### Final Answer The plot of the modulus of image distance versus object distance for a spherical mirror is a hyperbola. ---

To solve the question regarding the plot of the modulus of image distance versus object distance for a spherical mirror, we will follow these steps: ### Step 1: Understand the Mirror Formula The mirror formula relates the object distance (u), image distance (v), and focal length (f) of a spherical mirror: \[ \frac{1}{v} + \frac{1}{u} = \frac{1}{f} \] From this, we can express \( v \) in terms of \( u \): ...
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NARAYNA-RAY OPTICS AND OPTICAL INSTRAUMENTS -EXERCISE-2 (C.W)(REFLECTION)
  1. Two plane mirrors are arranged at right angles to each other as shown ...

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  2. An object moves with 5ms^(-1) toward right while the mirror moves wit...

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  3. Two mirror labelled L(1) for left mirror and L(2) for right mirror (L(...

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  4. A ray of light is incident at 50^(@) on the middle of one of the two m...

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  5. Two plane mirrors A and B are aligned parallel to each other, as shown...

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  6. With a concave mirror, an object is placed at a distance x(1) from the...

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  7. A short linear object of length b lies along the axis of a concave mir...

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  8. A rod of length 10 cm lies along the principal axis of a concave mirro...

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  9. A car is fitted with a convex side-view mirror of focal length 20 cm. ...

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  10. The velocity of image w.r.t ground in the below figure is

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  11. A square wire of side 3.0 cm is placed 25 cm away from a concave mirro...

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  12. An object is moving towards a concave mirror of focal length 24 cm. Wh...

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  13. The distance between an object and its doubly magnified image by a con...

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  14. In the figureshownm the image of a real object is formed at point I. A...

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  15. A ray of light is incident on a plane mirror along a vector hat i+hat ...

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  16. A plot of modulus of image distance versus object distance for a spher...

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  17. A small plane mirror kept at the centre of a sphere of diameter 3 m, m...

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  18. A man ‘A’ stands at the position shown in the figure and a second man ...

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