A beaker contains water up to a height `h_(1)` and kerosene of height `h_(2)` above water so that the total height of (water + kerosene) is `(h_(1) + h_(2))` . Refractive index of water is `mu_(1)` and that of kerosene is `mu_(2)` . The apparent shift in the position of the bottom of the beaker when viewed from above is :-

Options

A. `(1 -1/mu_(1))h_(1) + (1 - 1/mu_(2))h_(2)`
B. `(1 +1/mu_(1))h_(2) - (1 + 1/mu_(2))h_(1)`
C. `(1-1mu_(1))h_(2) + (1-1/mu_(2))h_(1)`
D. `(1+1/mu_(1))h_(1)-(1+1/mu_(2))h_(2)`

Answer

A

Explanation

`S=t(1-1/mu)`