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Two beam of light having intensities I a...

Two beam of light having intensities I and 4I interfere to produce a fringe pattern on a screen. The phase difference between the beams is `(pi)/(2)` at point A and `pi` at point B. Then the difference between resultant intensities at A and B is : `(2001 , 2M)`

A

2I

B

4I

C

5I

D

7I

Text Solution

Verified by Experts

The correct Answer is:
B
Here , `I_(1) = I, I_(2) = 4 I, theta_(1) = pi // 2 , theta _(2) = pi`
Resultant intensity
`I_(theta_(1)) = I_(1) + I_(2) + 2 sqrt(I_(1)I_(2)) cos theta_(1)`
` = I = 4 I + 2 sqrt(I xx 4 I) cos pi // 2 = 5I`
Resultant intensity
`I_(theta_(2)) = I_(1) + I_(2) + 2 sqrt(I_(1)I_(2)) cos theta_(2)`
`= I + 4 I + 2 sqrt(1 xx 4I) cos pi`
`= 5 I - 4 I = I :. I_(theta_(1)) - I_(theta_(2))= 5 I - I = 4 I`
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