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In young's double slit experiment, the 1...

In young's double slit experiment, the 10th maximum of wavelength `lambda_(1)`, is at a distance of `y_(1)` from the central maximum. When the wavelength of the source is changed to `lamda_(2)`, `5^(th)` maximum is at a distance of `y_(2)` from its central maximum. The ratio `( y_(1)/y_(2) )` is

A

`(2 lambda_(1))/(lambda_(2))`

B

`(2 lambda_(2))/(lambda_(1))`

C

`(lambda_(1))/(2 lambda_(2))`

D

`(lambda_(2))/(2 lambda_(1))`

Text Solution

Verified by Experts

The correct Answer is:
A
`y_(2) = 5 ((lambda_(2)D)/(d)) , y_(1) = 10 ((lambda_(1)D)/(d))`
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