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In a Young's double slit interference ex...

In a Young's double slit interference experiment the fringe pattern is observed on a screen placed at a distance D from the slits. The slits are separated by a distance d and are illuminated by monochromatic light of wavelength `lamda`. Find the distance from the central point where the intensity falls to (a) half the maximum, (b) one fourth of the maximum.

A

`(lambdaD)/(3d)`

B

`(lambda D)/(2d)`

C

`(lambda D)/(d)`

D

`(lambda D)/(4d)`

Text Solution

Verified by Experts

The correct Answer is:
D
` I= I_(0) "cos"^(2) (theta)/(2) , y = ((n lambda)D)/(d)`
`y = x.(D)/(d) = (lambda)/(4) (D)/(d)`
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