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For a parallel beam of monochromatic light of wavelength `'lambda'` diffraction is produced by a single slit whose width `'a'` is of the order of the wavelength of the light. If `'D'` is the distance of the screen from the slit, the width of the central maxima will be

A

`(Da)/(lambda)`

B

`(2Da)/(lambda)`

C

`(2 Dlambda)/(a)`

D

`(D lambda)/(a)`

Text Solution

Verified by Experts

The correct Answer is:
C

Central maxima ` = 2 xx beta`
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